Question 909087

if they have greatest common factor of {{{16}}},both are divisible by {{{16}}}

so,  let's numbers be {{{16x}}} and {{{16y}}}

if first one is {{{16x}}}, then next one must be  {{{2*16x=32x}}} which is equal to{{{16y}}}


if the sum of these two numbers is {{{384}}}, we have {{{16x+16y=16x+32x=384}}}

{{{16x+32x=384}}} ...solve for {{{x}}}

{{{48x=384}}}

{{{x=384/48}}}

{{{x=8}}}

so, your numbers are {{{16x=16*8=128}}} and {{{16y=32x=32*8=256}}}

check their sum: {{{128+256=384}}}