Question 908978
((b-2)(a+3) = ab + 10
ab  -2a + 3b - 6 = ab + 10
-2a + 3b = 16
b = {{{(16+2a)/3}}}
(1/2)(b+4)(a+4) = (1/2)ab + 42
(b+4)(a+4) = ab + 84
ab + 4a + 4b + 16 = ab + 84
4a + 4b = 68   Substitute for b to find a
4a + 4{{{(16+2a)/3}}} = 68 
12a + 4(16+2a) = 204
20a = 140
a = 7   and b  = 10 {{{(16+2*7)/3}}}