Question 908900
We know the total amount of money invested. $10637
x+y=10637,
We know that the difference in interest earned by the two accounts is $880.07
0.13*x-0.06*y=880.07
x=10637-y
We substitute for x
0.13*(10637-y)-0.06*y=880.07
We multiply out
1382.81-0.13y-0.06*y=880.07
We combine like terms.
502.74=0.19*y
Isolate y
y=502.74/0.19
y=2646.0 at 6%
Calculate x
x=10637-2646.0
x=7991 at 13%
Interest earned at 13% is 1038.83
Interest earned at 6% is 158.76
We check
0.13*7991-0.06*2646.0=880.07
1038.83-158.76=880.07
880.07=880.07
Since this statement is TRUE and neither x nor y  is negative then all is well