Question 908922
{{{33<abs(11-(11/3)x)}}}
{{{33<11abs(1-(1/3)x)}}}
{{{33/11<11*abs(1-(1/3)x)/11}}}
{{{3<abs(1-(1/3)x)}}}
That just for simplification, so easier to solve now.


Still more to simplify.
{{{3<abs(3/3-(1/3)x)}}}
{{{3<abs((3-x)/3)}}}
{{{3<(1/3)abs(3-x)}}}
{{{highlight_green(9<abs(3-x)*1)}}}.  (the factor of 1 unnecessary; only used for easier reading through the rendering outline)


Now, do you still need help with that?
Two conditions:  {{{3-x>=0}}} and {{{3-x<0}}}.


The results of that give {{{highlight(x<-6)}}}  OR  {{{highlight(x>12)}}}, which are connected as a union; the solution set is BOTH of them.
You could say the solution set is ({{{-infinity}}},-6) U (12,{{{infinity}}}).