<PRE><B>Question 908387</B>
Two cyclist start at the same time from opposite ends of the course that is 51 miles long. One cyclist is riding at a rate of 16 mph, and the second cyclist is riding at a rate of 18 mph. How long after they begin will they meet?
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Note: Their times are equal.
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x/16 = (51-x)/18
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18x = 16*51-16x
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34x = 816
x = 24 miles 
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Ans: Time = x/16 = 24/16 = 3/2 = 1 1/2 hours
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Cheers,
Stan H.
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