Question 76858
X^2+3X-40=0
(X-5)(X+8)=0
X-5=0
X=5 ANSWER.
X+8=0
X=-8 ANSWER.
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3X^2-4X+2=0
USING THE QUADRATIC EQUATION WE GET:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
X=(4+-SQRT[-4*-4-4*3*2])/2*3
X=(4+-SQRT[16-24])/6
X=(4+-SQRT-8)/6 BECAUSE THERE IS A NEGATIVE NUMBER UNDER THE SQRT SIGN THE ANSWERS WILL NOT BE REAL ROOTS. THUS
X=(4+-2.83i)/6
X=4/6+2.83i/6 
X=2/3+,47i ANSWER.
X=(4-2.38i)/6
X=4/6-2.38i/6
X=2/3-.47i ANSWER.