Question 907997
Find the point of intersection.
When {{{x=30}}},
{{{5(30)-6y=24}}}
{{{150-6y=24}}}
{{{-6y=-122}}}
{{{y=21}}}
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Perpendicular lines have slopes that are negative reciprocals.
{{{5x-6y=24}}}
{{{-6y=-5x+24}}}
{{{y=(5/6)x-4}}}
So the perpendicular line would have a slope of ,
{{{m*(5/6)=-1}}}
{{{m=-6/5}}}
Use the point-slope form of a line.
{{{y-21=-(6/5)(x-30)}}}
{{{5(y-21)=-6(x-30)}}}
{{{5y-105=-6x+180}}}
{{{highlight(6x+5y=285)}}}