Question 908103
The given equation, {{{3x+2y=3x-7}}}
{{{is 2y=-7}}}
{{{highlight_green(y=-7/2)}}}, and the slope is 0, a horizontal line.


The lines perpendicular to {{{y=-7/2}}} have no slope. They are vertical.
The point (3,-2) will be on the line {{{highlight(x=3)}}}, which is perpendicular to the given {{{y=-7/2}}}.


You could arrange the equation of the line found as {{{highlight(0=x-3)}}} and this has no restriction for y.