Question 907960
You can think of this as
one of them standing still and
the other traveling at the sum of their speeds
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Let {{{ t }}} = The time in hrs until they meet
{{{ 2160 = ( 55 + 65 )*t }}}
{{{ t = 2160 / 120 }}}
{{{ t = 18 }}} hrs
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Let {{{ d[1] }}} = distance Mark travels
{{{ d[1] = 65t }}}
{{{ d[1] = 65*18 }}}
{{{ d[1] = 1170 }}}
Mark travels 1170 mi
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check:
Linda travels:
{{{ d[2] = 55t }}}
{{{ d[2] = 55*18 }}}
{{{ d[2] = 990 }}} mi
and
{{{ d[1] + d[2] = 1170 + 990 }}}
{{{ d[1] + d[2] = 2160 }}}
OK