Question 907844
Did you mean the last term to be {{{16(2x+5)^3(10x-1)^8}}}???
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{{{12(2x+5)^4(10x-1)^7 + 16(2x+5)^3(10x-1)^8=4(2x+5)^3(10x-1)^7*(3(2x+5)+4(10x-1))}}}

{{{12(2x+5)^4(10x-1)^7 + 16(2x+5)^3(10x-1)^8=4(2x+5)^3(10x-1)^7*(6x+15+40x-4)}}}
{{{12(2x+5)^4(10x-1)^7 + 16(2x+5)^3(10x-1)^8=4(2x+5)^3(10x-1)^7*(46x+11)}}}