Question 907650
{{{sin^2(theta)+cos^2(theta)=1}}}
{{{(-3/5)^2+cos^2(theta)=1}}}
{{{9/25+cos^2(theta)=1}}}}
{{{cos^2(theta)=25/25-9/25}}}
{{{cos^2(theta)=16/25}}}
{{{cos(theta)=0 +- 4/5}}}
Since {{{pi < theta < (3/2)pi}}},
{{{cos(theta)=-4/5}}}
So then,
{{{tan(theta)=sin(theta)/cos(theta)}}}
{{{tan(theta)=(-3/5)/(-4/5)}}}
{{{highlight_green(tan(theta)=3/4)}}}