Question 907630
{{{a^2+b^2=c^2}}}
{{{(c-6)^2+(c-3)^2=c^2}}}
{{{c^2-12c+36+c^2-6c+9=c^2}}}
{{{c^2-18c+45=0}}}
{{{(c-3)(c-15)=0}}}
Two solutions:
{{{c-3=0}}}
{{{c=3}}}
However this solution doesn't work since the leg lengths would be {{{b=0}}} and {{{a=-3}}}.
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{{{c-15=0}}}
{{{c=15}}}
Then,
{{{a=15-6}}}
{{{a=9}}}
and
{{{b=15-3}}}
{{{b=12}}}