Question 907520
Is it possible for x = -2 to be in the Domains of the functions
a) R(x) = (3x^3 - 5x + 6)/(x+2)
If x=-2, denominator=0, making function undefined.
x≠-2
domain: (-inf,-2) U (2,inf)

b) H(x) = {{{ sqrt (x+1) }}}
If x=-2, radican becomes <0, which is not allowed by definition.
x&#8800;-2
domain: (-inf,-2) U (2,inf)