Question 76783
at 0 yards away from the quarterback the ball is 2 meters above the ground
(0,2)
at the vertex, the ball is 20 yards away from the quarterback and 14 meters high
(20,14)
y = a(x - h)^2 + k
y = a(x - 20)^2 + 14
2 = a(0 - 20)^2 + 14
-12 = 400a
-3/100 = a
Equation: y = (-3/100)(x - 20)^2 + 14
{{{graph(600,200,-10,45,-2,14,(-3/100)(x - 20)^2 + 14)}}}