Question 907423
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Both problems are done the same way.  Calculate *[tex \Large f(a)] and *[tex \Large f(b)].  If the sign of *[tex \Large f(a)] is different than the sign of *[tex \Large f(b)], then for a function that is continuous over the given interval, there is at least one real zero in the interval.  If the signs are the same, the existence of a zero cannot be guaranteed, nor can the possibility be eliminated.  Both of your problems are polynomial functions so there are no continuity issues.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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