Question 907311
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Assume your triangle has hypotenuse *[tex \Large h], side opposite the 43 degree angle of *[tex \Large a], and the third side *[tex \Large b].


Since the sum of the two acute angles of any right triangle must be 90, the third angle in this triangle is 47 degrees.


From the trigonometry of a right triangle we know that the measure of side *[tex \Large a] is given by *[tex \Large h\sin 43], the measure of side *[tex \Large b] is given by *[tex \Large h\sin 47], and the measure of the hypotenuse is simply *[tex \Large h], hence:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ h\sin 43\ +\ h\sin 47\ +\ h\ =\ 30]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ h\ =\ \frac{30}{\sin 43\ +\ \sin 47\ +\ 1}]


Solve for *[tex \Large h] and then you can calculate the other two sides using the previously given relationships.  Hint:  Remember to set your calculator to degree mode.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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