Question 907296
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2(x\ -\ 5)(2x\ +\ 3)\ +\ 2(x\ -\ 5)^2\ =\ 0]


Factor out *[tex \Large 2(x\ -\ 5)]:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2(x\ -\ 5)\left((2x\ +\ 3)\ +\ (x\ -\ 5)\right)\ =\ 0]


Collect like terms:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \ 2(x\ -\ 5)(3x\ -\ 2)\ =\ 0]


Apply the zero product rule:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ -\ 5\ =\ 0\ \Rightarrow\ x\ =\ 5]


Or


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3x\ -\ 2\ =\ 0\ \Rightarrow x\ =\ \frac{2}{3}]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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