Question 907171
I would call this a problem about
Worst Case Scenarios ( WCS )
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If you are drawing bags from a randomly
mixed barrel of bags, and you draw
7 bags, what is the WCS if you are 
looking for 3 bags with the same number
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The WCS is that you draw 51, 52, 53, ... 57
to start with, or, no duplicates at all
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But if you draw 1 more bag, you are now
guaranteed 1 duplicate
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Each time you pick 7 more bags, you are
guaranteed in a WCS, that you will only 
get another duplicate, but not the one
you wanted
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If you do {{{ 7*7 = 49 }}} picks, then you
are guaranteed 2 of each kind as a WCS
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On the 50th pick of bags, you are finally
GUARANTEED a WCS of 3 bags with the
same number of kisses
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An example of a WCS series of 7 picks is:
(1) 51, 52, 53, 54, ... 57
(2) 51, 51, 51, 51, ... 51
(3) 52, 52, 52, 52, ... 52
(4) 53, 53, 53, 53, ... 53
. 
.
.
(7) 57, 57, 57, 57, ... 57
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Note that you don't have 3 that
are the same yet, but 1 more
pick guarantees that you will
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So, you need to pick 50 bags