Question 76697
Graph
 
y=-1/3x+1
Let x=0 and solve for y
y=-1/3(0)+1
y=0+1
y=1  Plot (0,1)
Let x=3 and solve for y
y=-1/3(3)+1
y=-1+1
y=0  Plot (3,0)
Connect the points and you have 
{{{graph(300,200,-10,10,-10,10,(-1/3)x+1)}}}

 
y=1/3x+1
Let x=0 and solve for y
y=(1/3)(0)+1
y=0+1
y=1  Plot (0,1)
Let x=-3 and solve for y
y=1/3(-3)+1
y=-1+1
y=0  Plot (-3,0)
Connect the points and you have
{{{graph(300,200,-10,10,-10,10,(1/3)x+1)}}}
:
Both of these lines are in slope intercept form: {{{highlight(y=mx+b)}}}, m=slope and (0,b)=y-intercept.
Their slopes have opposite signs, but the same y-intercept (0,1).  If you were supposed of graph these two points together, you would find that they intersect at (0,1).  If this is a system, then that's the solution to the system of equations.
{{{graph(300,200,-10,10,-10,10,(-1/3)x+1,(1/3)x+1)}}}
Happy Calculating!!!!