Question 906574
as far as i can see, none of them are equal.


A is the set {1,2,3}
there are 3 elements in the set.
those elements are x = 1, x = 2, x = 3.


B is solved for as follows:
x^2 - 2x + 1 = 0
factor this to get (x-1)^2 = 0
that gets you x = 1 as the only value of x in the set.


C is solved for as follows:
start with x^3 - 6x^2 + 11x - 6 = 0
your rational roots, if any, will be a combination of the factors of the coefficient of x^3 multiplied by the factors of the constant term.
that would make the possible roots as plus or minus {6,3,2,1)
you can use synthetic division to eliminate these possibilities.
6 is not a root, but 1, 2, and 3 are all roots.


selections A and C are equivalent.


if you need help on how to perform synthetic division, here's a reference.


<a href = "http://www.wtamu.edu/academic/anns/mps/math/mathlab/col_algebra/col_alg_tut37_syndiv.htm" target = "_blank">http://www.wtamu.edu/academic/anns/mps/math/mathlab/col_algebra/col_alg_tut37_syndiv.htm</a>


if you need help on how to determine the rational roots of an equation, here's a reference that can help.


<a href = "http://www.wtamu.edu/academic/anns/mps/math/mathlab/col_algebra/col_alg_tut38_zero1.htm" target = "_blank">http://www.wtamu.edu/academic/anns/mps/math/mathlab/col_algebra/col_alg_tut38_zero1.htm</a>