Question 76678
Find the length of each side of the rectangle so that it has the given perimeter.    
Note:  Perimeter = 2*length + 2*width
Length= 2x-5
Width= x
	 
p=50 in.
{{{50=2(2x-5)+2(x)}}}
{{{50=4x-10+2x}}}
{{{50=6x-10}}}
{{{50+10=6x-10+10}}}
{{{60=6x}}}
{{{60/6=6x/6}}}
{{{10=x}}}
Length=2x-5= 2(10)-5=20-5=15 in.
Width=x=10 in
Sanity check, does a rectangle with a length of 15 in and a width of 10 in have a peimeter that is 50 in?
50=2(15)+2(10)
50=30+20
50=50
We're not off our rocker!!!!
Happy Calculating!!!!