<PRE><B>Question 906435</B>
An isosceles right triangle has legs measuring (x-2) cm each. the hypotenuse has measure (x+4) cm. find x
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(x-2)^2 + (x-2)^2 = (x+4)^2
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2[x^2-4x+4] = x^2 + 8x + 16
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2x^2 - 8x + 8 = x^2 + 8x + 16
x^2 - 16x - 8 = 0
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x = [16 +- sqrt(16^2-4*-8)]/2
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x = [16 +- sqrt(288)]/2
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x = [16 +- 16.97]/2
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x = 16.49 or x = -0.49
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Cheers,
Stan H.
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