Question 906422
Let f (x) = x^2+4x-7
(a) Find the coordinates of the vertex.
complete the square:
y=x^2+4x-7
y=(x^2+4x+4)-4-7
y=(x+2)^2-11
(x, y) = (-2,-11)
..
(b) The [Either max/min] value of f is
f ( min ) y=-11
..
(c)domain: (-∞,∞)
 range:(-11,∞)