Question 904251
log ( 4p + 1) + log (p) = log (3)

Remember the log rule :

log x + log y = log xy


Therefore, log ( 4p +1) + log (p) = log (3)
           log  p( 4p + 1) = log 3

When the bases are the same , then we can make p(4p+1) = 3

This will give us 4p^2 + p -3 =0
 which is (4p-3)(p+1) =0
4p-3 =0      
4p =3        
p= 3/4    

p+1 =0
p= -1

Since we cannot have a negative inside a logarithm, we can only take p= 3/4 as the answer.