Question 906306
the standard slope-intercept form for an equation of a line is 
{{{y = highlight_green(m)x + highlight(b)}}}  where m is the slope and b the y-intercept.  
5x + 3y = 18 0r y = (-5/3)x + 6, m = (-5/3)
New line:  m = {{{  highlight_green(3/5) }}}  as {{{(-5/3)(3/5) = -1}}} (I think of 3/5 as the negative reciprocal of -5/3)
***Using point-slope form, {{{y - y[1] = m(x - x[1])}}}P(0,0)
y-0 = (3/5)(x-0)
y = (3/5)x  in slope-intercept form