Question 906226
You have a strict inequality, based on the line {{{y=x/3+2}}}, so instead of darkening the line, you EXCLUDE it  (because you have {{{y<x/3+2}}}, not the equation), and you shade the region below the line.  On paper, you would show a dotted line for the reference equation, not a solid line.  As YOU described, you have no misunderstanding, so what help you need seems not to be any.


You specifically request to have the points LABELED when it is graphed.  The solution to the inequality IS NOT A POINT.  The solution is a REGION BELOW AND EXCLUDING the reference line.  You need to understand that you are not missing anything and need to recognize that you are not missing anything.  We do not label the solution points; we SHADE the solution region.


The line is supposed to be dotted, not solid, although you may be unable to distinguish if it appears dotted or not, but the code for this graph IS entered as a strict inequality.

{{{graph(300,300,-6,6,-6,6,y<x/3+2)}}}