Question 906047
Each absolute value expression has two possible cases.  The expression inside is nonnegative or it is negative.  Evaluate each case.  Your inequality statement has two absolute values, so there are FOUR cases to check.


CASE {{{x+1>=0}}} and {{{2x-1>=0}}}


CASE  {{{x+1<0}}} and {{{2x-1>=0}}}


CASE {{{x+1>=0}}} and {{{2x-1<0}}}


CASE {{{x+1<0}}} and {{{2x-1<0}}}


Can you make the simplifications to the inequality for each case and solve for it?