Question 905970
complete the table given {{{y= (2/3)x + 1}}}

X    | Y   |
_____|_____|
0____|_____|
_____|_-2__|
-3___|_____|
_6___|_____|


if {{{x=0}}}=>{{{y= (2/3)0 + 1=1}}}
if {{{y=-2}}}=>{{{-2= (2/3)x + 1}}} =>{{{-2-1= (2/3)x }}} =>{{{-3/(2/3)= x }}} =>{{{-3*3/2= x }}} =>{{{-9/2= x }}}

if {{{x=-3}}}=>{{{y=(2/3)(-3))+ 1=-2+1=-1}}}

if {{{x=6}}}=>{{{y= (2/3)6 + 1=2*6/3+1=12/3+1=4+1=5}}}

so, your table will be:


X    | Y   |
_____|_____|
0____|__1___|
-9/2_|_-2__|
-3___|_-1___|
_6___|__5___|