Question 905890
{{{A=3B}}}
{{{B=(5/2)C}}}
{{{A+B+C=66}}}
From eq. 2,
{{{C=(2/5)B}}}
Substitute,
{{{3B+B+(2/5)B=66}}}
{{{(15/5+5/5+2/5)B=66}}}
{{{(22/5)B=66}}}
{{{B=15}}}
Now that you know Bailey's age, work backwards to find Addison and Christopher's ages.