Question 904917
{{{y=mx+b}}}
{{{y=-(1/4)x+b}}}
When {{{y=0}}}, {{{x=-1/4}}}
{{{0=-(1/4)(-(1/4))+b}}}
{{{b=-1/16}}}
So then,
{{{y=-(1/4)x-1/16}}}
So when {{{x=0}}},
{{{y=-(1/4)(0)-1/16}}}
{{{y=-1/16}}}
So,
{{{b=-1/16}}}