Question 905815

The interior angles of any polygon always add up to a constant value, which depends only on the number of sides.
The sum of the interior angles of a polygon is given by the formula :

{{{sum=180(n-2)}}} degrees where {{{n}}} is the number of sides

you are given {{{ sum=1300}}}

so, plug it is {{{sum=180(n-2)}}}

{{{1300=180(n-2)}}} ...solve for {{{n}}}

{{{1300/180=n-2}}}

{{{7.22=n-2}}}

{{{7.22+2=n}}}

{{{9.22=n}}}

since the number of the sides is decimal number, answer is:  it is {{{not}}} possible to draw a polygon that has interior angles that sum up to {{{1300}}}