Question 905819
an equation of the line containing the point ({{{-1}}},{{{3}}})and perpendicular to the line {{{x + 2y = -6}}}:

{{{x + 2y = -6}}}...solve for {{{y}}}

{{{2y =-x-6}}}

{{{y = -(1/2)x-6/2}}}

{{{y = -(1/2)x-3}}}


*[invoke equation_parallel_or_perpendicular "perpendicular", "-1/2", -3, -1, 3]