Question 905608
6(-7 + 6i)(-4 + 2i)


6[(-7 + 6i)(-4 + 2i)]


6[-7(-4 + 2i) + 6i(-4 + 2i)]


6[-7(-4) - 7(2i) + 6i(-4) + 6i(2i)]


6(28 - 14i - 24i + 12i^2)


6(28 - 14i - 24i + 12(-1))


6(28 - 14i - 24i - 12)


6(16 - 38i)


6(16) + 6(-38i)


<font color="red">96 - 228i</font>


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So, 6(-7 + 6i)(-4 + 2i) = <font color="red">96 - 228i</font> and it is in the form a+bi where a = 96 and b = -228