Question 905428
Using Pythagorean Theorem
(17t)^2 + (14(t-1))^2 = 35mi^2
289t^2 + 196(t^2 - 2t + 1) = 1225mi
 485t^2 -392t - 1029 = 0

 *[invoke quadratic "x",485,-392,-1029]