Question 905319
x, y,

{{{xy=16}}} and {{{y-x=1}}}


y=x+1;
{{{x(x+1)=16}}}
{{{x^2+x-16=0}}}


{{{x=(-1+-sqrt(1+4*16))/2}}}
{{{highlight(x=(-1+sqrt(65))/2)}}};
you can find y.