Question 905317
Let w and L be the dimensions of the cardboard before cutting and folding.


Cut the 2 cm square corners and fold:


Area of the base, {{{(w-2*2)(L-2*2)}}}.


Perimeter of the base supposed to be {{{2(w-4)+2(L-4)=60}}}
{{{2w-8+2L-8=60}}}
{{{2w+2L=60+16}}}
{{{2w+2L=76}}}
{{{w+L=38}}}


Volume of the box given as 224, so
{{{highlight_green((w-4)(L-4)*2=224)}}}
{{{(w-4)(L-4)=112}}}


Now just work with the system
{{{highlight(system((w-4)(L-4)=112,w+L=38))}}}  to solve for w and L.