Question 905257
Syed and Jenny are 18 km apartwith Syed behind Jenny. They begin to walk at the same time. If they walk in the same direction they meet after 6 hours. If they walk towards each other they meet in 2 hours. Find their speed.
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let x=Syed's speed
let y=Jenny's speed
speed walking in the same direction = x-y
speed walking toward each other = x+y
travel time*speed=distance
..
6(x-y)=18
2(x+y)=18
..
6x-6y=18
2x+2y=18
..
6x-6y=18
6x+6y=54
add
12x=72
x=6
2y=18-2x=6
y=3
Syed's speed=6 km/hr
Jenny's speed=3 km/hr