Question 905270
Total amount of money invested: $30000
x+y=30000,
Total yearly interest for the two accounts is: $1440
0.1*x+-0.03*y=1440
x=30000-y
Substitute for x
0.1*(30000-y)+-0.03*y=1440
Multiply out
3000-0.1y+-0.03*y=1440
Combine like terms.
-0.13*y=-1560
Isolate y
y=$12000.00 at -3%
x=30000-y
Calculate x
x=$18000.00 at 10%
Check
0.1*18000+-0.03*12000=1440
1800+-360=1440
1440=1440