Question 905169
g(x) = 5(x - 3)^2 + 10
<pre>
You have to learn about the graph of equations in the form

f(x) = a(x - h)^2 + k, 

[just like you had to learn about the graph of equation in 
the form of y = mx+b, which were straight lines.]

The graph of equations in the form

f(x) = a(x - h)^2 + k

are not lines, but are U-shaped curved graph, a right-side up U
if "a" is a positive number,  and the U is upside-down if "a"
is a negative number.

The vertex is the point (h,k).  The vertex is the bottom of the 
U (a MINIMUM pointr) or the top of the upside-down U, (a MAXIMUM
point) 

Notice that the sign of h is changed but the sign of k is not.

So the graph of your equation

g(x) = 5(x - 3)^2 + 10

has a=5, h=3, and k=10

So since "a" is a positive number 5, the graph is a right side up 
U-shaped graph with the bottom (MINIMUM) point of the U being 
the point (h,k) = (3,10).

Here's the graph

{{{drawing(400,400,-9,9,-3,15, graph(400,400,-9,9,-3,15,5(x - 3)^2 + 10),
locate(3,10,"(3,10)"))

}}}

Edwin</pre>