Question 76544
Factor completely:
1)
{{{x^2+17x+16 = (x+1)(x+16)}}}

2)
{{{3x^2-75y^2}}} First, factor a 3.
{{{3(x^2-25y^2)}}} Now, can you see that the parentheses contain the difference of two squares?:{{{(x)^2-(5y)^2}}}.
The difference of two squares can be factored thus:
{{{A^2-B^2 = (A+B)(A-B)}}} Applying this to your problem, you will get:
{{{3x^2-75y^2 = 3(x+5y)(x-5y)}}}...and there it is!