Question 76541
a little factoring and regrouping will illuminate your answer


y=x^2-6x+8 may be rewritten as y=1(x^2-6x)+8..."completing the square" gives y=1(x^2-6x+9)+8-9...the +9 added inside the parentheses is "compensated" by the -9 added outside


note that if the coefficient of the x^2 term is something besides 1, the "compensation" is affected accordingly


factoring and consolidating terms gives y=1(x-3)^2-1...so a=1, h=3 and k=-1