Question 904768
Distance where she meets the log = 2miles

speed of current = speed of log =y

let speed of canoe in still water be x

speed upstream = (x-y)
speed downstream = (x+y)


she travels upstream for 1 hour
d=rt
so distance she travels upstream = (x-y)

Time taken to reach starting point 

time taken upto the point where she met the log and time taken for 2 miles downstream

= t=d/r

d= (x-y),(x-y), 2

t= 1+((x-y)/(x+y))+2/(x+y) =2/y

1+(2+x-y)/(x+y)=2/y

((x+y)+(2+x-y))/(x+y) =2/y

y(2+2x )=2(x+y)

2y+2xy=2x+2y

2x=2xy

y=1mph the speed of the current