Question 10202
The first step is to get this equation, if it really is a quadratic equation,  into the standard quadratic form: {{{ax^2+bx+c=0}}}

{{{(1/12) + (3/x) = (2/x) + 1}}} Add the fractions on the left side and on the right side.
{{{(x+36)/12x = (2+x)/x}}} Multiply both sides by (12x)
{{{12x(x+36)/12x = 12x(2+x)/x}}} Simplify.
{{{x+36 = 24+12x}}} Subtract x from both sides.
{{{36 = 24 + 11x}}} Subtract 24 from both sides.
{{{12 = 11x}}} Since there is no x^2 term, you don't have a quadratic equation.

{{{x = 12/11}}}