Question 904549
Total amount of money invested: $12000
x+y=12000,
Total yearly interest for the two accounts is: $1065
0.08*x+0.115*y=1065
x=12000-y
Substitute for x
0.08*(12000-y)+0.115*y=1065
Multiply out
960-0.08y+0.115*y=1065
Combine like terms.
0.035*y=105
Isolate y
y=$ 3000.00 at 11.5%
x=12000-y
Calculate x
x=$ 9000.00 at 8%
Check
0.08*9000+0.115*3000=1065
720+345.0=1065
1065.0=1065
If this statement is TRUE and neither amount is negative then all is well

$3000 is the least that you can invest at 11.5 % to get at least $1065.
if all $12000 were invested at 11.5% the interest would be $1380