Question 76472
If you picture the arch with the base sitting on the x-axis and centered on the y-axis, it is an ellipse with a major axis of 20 and a minor axis of 16 centered at the origin (0,0)


the equation of this ellipse is {{{(x^2)/10^2+(y^2)/8^2=1}}}...or {{{16x^2+25y^2=1600}}}


at x=6 (or -6) the equation is {{{576+25y^2=1600}}}...or {{{25y^2=1024}}}...or 5y=32...so y=6.4 and height is 6.4 feet