Question 904338
{{{z[1]=2+7i}}} and {{{z[2]=4-3i}}}
{{{z[1]/z[2]=(2+7i)/(4-3i)}}}
At this point you would multiply times {{{(4+3i)/(4+3i)=1}}} ,
or as you would say, multiply top and bottom by {{{(4+3i)}}} ,
which is the conjugate of denominator {{{4-3i}}} .
That will give you a denominator that is a real number.
{{{z[1]/z[2]=(2+7i)/(4-3i)=(2+7i)(4+3i)/((4+3i)(4-3i))}}}={{{(8+6i+28i+21i^2)/(4^2-(3i)^2)=(8+34i-21)/(16-9i^2)}}}={{{(-13+34i)/(16+9)=(-13+34i)/25=-13/25+(34/25)i}}}