Question 904355
	percent	----------------			quantity									
Alcohol type I	5.00%	----------------			x	ml								
Alcohol type II	90.00%	------	340	-	x	ml								
Mixture	45.00%	----------------	340											
Total	340		ml											
5.00%	x	+	90.00%	(	340	-	x	)	=	45.00%	*	340		
5	x	+	90	(	340	-	x	)	=	15300				
5	x	+	30600	-	90	x	=			15300				
5	x	-	90	x			=	15300	-	-30600				
-85	x			=	-15300									
/	-85													
	x			=	180		ml			5.00%		Alcohol type I		
					160		ml			90.00%		Alcohol type II		
														
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