Question 76441
n+d+q=57...5n+10d+25q=1000...q=3n+2...substituting the value of q from the third equation into the first two equations gives


A)n+d+3n+2=57...and B)5n+10d+75n+50=1000..multiplying equation A by 10 and subtracting the result from equation B gives


5n+10d+75n+50-10n-10d-30n-20=1000-570...rearranging and combining terms gives...40n=400 or n=10...so q=32 and d=15