Question 76447
3X^2-4X+2=0
USING THE QUADRATIC EQUATION
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
YOU'LL FIND OUT THAT THERE ARE NO REAL ROOTS!
X=(4+-SQRT[-4^2-4*3*2])/2*3
X=(4+-SQRT[16-24])/6
X=(4+-SQRT-8)/6 ANY SQUARE ROOT OF A NEGATIVE NUMBER (-8) RESULTS IN A ROOT NUMBER FOLLOWED BY AN (i) INDICATING IT IS NOT A REAL NUMBER.