Question 903742
h(t) = {{{5t/(t-1)}}}


k(t) = {{{9/(3t+7)}}}


(hok)(t) is equal to h(k(t))


basically, you are replacing the t in h(t) with k(t)).


you will get:


h(k(t)) = {{{(5*(9/(3t+7)))/(9/(3t+7)-1)}}}


if you solve it correctly, you should get:


h(k(t)) = {{{45/(2-3t)}}}